"Tm=Tp,(Hp+NX)/Rm=Hm/Rp+NTe,N=(HmRm/Rp-Hp)/(X-TeRm).See our clan page for details"

XTm = Tp, where T is fight time, p is player, & m is monster.
Hp/Rm = Hm/Rp, where H is health and R is damage rate (no food).

Let M be N

WITH 1 TYPE OF FOOD:
(Hp + MX)/Rm = Hm/Rp + NTe, where Te is time to eat 1, & X is heal per food.
M = (HmRm/Rp - Hp)/(X - TeRm), after rearranging the above. N is # of food.
0 <= N <= Nt, where Nt is the upper limit for M.

WITH 2 TYPES OF FOODS:
(Hp + N1X1 + M2X2)/Rm = Hm/Rp + N1Te1 + N2Te2, where 1 & 2 are food types.
N1(Te1Rm - X1) + N2(Te2Rm - X2) = Hp - HmRm/Rp, after rearranging the above.
Let N1 + N2 = Nt, where Nt is a set upper bound for total food per trip.

After solving for N1 & N2:
N1 = Nt - (Hp - HmRm/Rp + X1Nt - Te1RmMt) / (Te2Rm - Te1Rm + X1 - X2)
N2 = (Hp - HmRm/Rp + X1Nt - Te1RmMt) / (Te2Rm - Te1Rm + X1 - X2)
Note N1 >= 0 & N2 >= 0

IF SARADOMIN BREW IS USED (RS2007):
Let X = 60, but there must be a restore potion per 3 brews.
Therefore, let X = 3(60)/4 = 45 (45hp per iventory on average)